Mister Exam
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How to use it?
- Express {x} in terms of y where:
- -18*x+19*y=2
- 14*x+1*y=12
- 9*x+6*y=2
- 3*x-7*y=0
- Equation:
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Equation x^2+2x+1=0
-
Equation cos(x/2)=1/2
-
Equation sin(x)=1,5
-
Equation 4*x^2-7*x-2=0
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Identical expressions
- - eighteen *x+ nineteen *y= two
- minus 18 multiply by x plus 19 multiply by y equally 2
- minus eighteen multiply by x plus nineteen multiply by y equally two
- -18x+19y=2
-
Similar expressions
- -18*x-19*y=2
- 18*x+19*y=2
Express x in terms of y where -18*x+19*y=2
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 18 x = 2 - 19 y$$
Divide both parts of the equation by -18
We get the answer: x = -1/9 + 19*y/18
-18*x+19*y = 2
Looking for similar summands in the left part:
-18*x + 19*y = 2
Move the summands with the other variables
from left part to right part, we given:
$$- 18 x = 2 - 19 y$$
Divide both parts of the equation by -18
x = 2 - 19*y / (-18)
We get the answer: x = -1/9 + 19*y/18
Rapid solution
[src]
1 19*re(y) 19*I*im(y)
x1 = - - + -------- + ----------
9 18 18
$$x_{1} = \frac{19 \operatorname{re}{\left(y\right)}}{18} + \frac{19 i \operatorname{im}{\left(y\right)}}{18} - \frac{1}{9}$$
x1 = 19*re(y)/18 + 19*i*im(y)/18 - 1/9