Mister Exam
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How to use it?
- Equation:
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Equation x/4+13=x+1
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Equation 2x^2-x-1=x^2-5x-(-1-x^2)
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Equation x^3-x^2-x-1=0
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Equation -x=3
- Express {x} in terms of y where:
- 10*x-2*y=11
- -18*x-14*y=12
- 4*x+8*y=7
- -14*x+5*y=3
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Identical expressions
- zero , two x+2, seven = one , four - one ,1x
- 0,2x plus 2,7 equally 1,4 minus 1,1x
- zero , two x plus 2, seven equally one , four minus one ,1x
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Similar expressions
- 0,2x-2,7=1,4-1,1x
- 0,2x+2,7=1,4+1,1x
0,2x+2,7=1,4-1,1x equation
The teacher will be very surprised to see your correct solution 😉
The solution
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x 27 7 11*x - + -- = - - ---- 5 10 5 10
$$\frac{x}{5} + \frac{27}{10} = \frac{7}{5} - \frac{11 x}{10}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = - \frac{11 x}{10} - \frac{13}{10}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{13 x}{10} = - \frac{13}{10}$$
Divide both parts of the equation by 13/10
We get the answer: x = -1
(1/5)*x+(27/10) = (7/5)-(11/10)*x
Expand brackets in the left part
1/5x+27/10 = (7/5)-(11/10)*x
Expand brackets in the right part
1/5x+27/10 = 7/5-11/10x
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = - \frac{11 x}{10} - \frac{13}{10}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{13 x}{10} = - \frac{13}{10}$$
Divide both parts of the equation by 13/10
x = -13/10 / (13/10)
We get the answer: x = -1
The graph