Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+2x+1=0
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Equation cos(x)+1=0
- Equation a*4a
- Equation 5x=4x+7
- Express {x} in terms of y where:
- -10*x-7*y=1
- -5*x-12*y=19
- -10*x-8*y=12
- -19*x-17*y=1
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Identical expressions
- zero , six (x+ seven)= zero , five (x- three)
- 0,6(x plus 7) equally 0,5(x minus 3)
- zero , six (x plus seven) equally zero , five (x minus three)
- 0,6x+7=0,5x-3
- 0,6(x+7)=O,5(x-3)
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Similar expressions
- -0,6x+7=0
- 0,6(x-7)=0,5(x-3)
- ((x-2)^0,5)*((x-3)^0,5)=0
- 0,6(x+7)=0,5(x+3)
0,6(x+7)=0,5(x-3) equation
The teacher will be very surprised to see your correct solution 😉
The solution
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3*(x + 7) x - 3
--------- = -----
5 2
$$\frac{3 \left(x + 7\right)}{5} = \frac{x - 3}{2}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{5} = \frac{x}{2} - \frac{57}{10}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{x}{10} = - \frac{57}{10}$$
Divide both parts of the equation by 1/10
We get the answer: x = -57
(3/5)*(x+7) = (1/2)*(x-3)
Expand brackets in the left part
3/5x+7 = (1/2)*(x-3)
Expand brackets in the right part
3/5x+7 = 1/2x-3
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{5} = \frac{x}{2} - \frac{57}{10}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{x}{10} = - \frac{57}{10}$$
Divide both parts of the equation by 1/10
x = -57/10 / (1/10)
We get the answer: x = -57