Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+2x+1=0
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Equation cos(x)+1=0
- Equation (9525+15031+11519+11193+10272+11826+10482+11932+12586+x)/10=11000
- Equation a*4a
- Express {x} in terms of y where:
- -7*x+10*y=8
- -7*x+15*y=-2
- -1*x+6*y=2
- -19*x+9*y=11
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Identical expressions
- a*4a
- a multiply by 4a
- a4a
-
Similar expressions
- a^4*a^11/a^x=a^2
- a*(4*a-1)-5*(4*a-1)=0
- x^2*(x^2-4*a*x+6*a^2-2)+1=a*(4*a^2*x-4*x-2*a-a^3)
- 10*a*(4*a+6)-(26*a^2-16*a)-76*a=0
a*4a equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$a 4 a = 0$$
so
$$a = 0$$
We get the answer: a = 0
$$a 4 a = 0$$
so
$$a = 0$$
We get the answer: a = 0
Vieta's Theorem
rewrite the equation
$$a 4 a = 0$$
of
$$a^{3} + a b + c = 0$$
as reduced quadratic equation
$$a^{2} + b + \frac{c}{a} = 0$$
$$a^{2} = 0$$
$$a^{2} + a p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$a_{1} + a_{2} = - p$$
$$a_{1} a_{2} = q$$
$$a_{1} + a_{2} = 0$$
$$a_{1} a_{2} = 0$$
$$a 4 a = 0$$
of
$$a^{3} + a b + c = 0$$
as reduced quadratic equation
$$a^{2} + b + \frac{c}{a} = 0$$
$$a^{2} = 0$$
$$a^{2} + a p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$a_{1} + a_{2} = - p$$
$$a_{1} a_{2} = q$$
$$a_{1} + a_{2} = 0$$
$$a_{1} a_{2} = 0$$