y(n+2)+y(n+1)-6y(n) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
y*(n+2)+y*(n+1)-6*y*(n) = 0
Expand brackets in the left part
yn+2+yn+1-6*yn = 0
Looking for similar summands in the left part:
y*(1 + n) + y*(2 + n) - 6*n*y = 0
Divide both parts of the equation by (y*(1 + n) + y*(2 + n) - 6*n*y)/y
y = 0 / ((y*(1 + n) + y*(2 + n) - 6*n*y)/y)
We get the answer: y = 0
Sum and product of roots
[src]
$$0$$
$$0$$
$$0$$
$$0$$