Mister Exam
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- Equation:
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Equation 2*sin(x)=0
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Equation -2*(-y-2)-y-2=0
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Equation 12-x=6
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Equation 12/(x+5)=-12/5
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -11*x-3*y=-15
- 5*x-18*y=-17
- 15*x-20*y=4
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Identical expressions
- twelve /(x+ five)=- twelve / five
- 12 divide by (x plus 5) equally minus 12 divide by 5
- twelve divide by (x plus five) equally minus twelve divide by five
- 12/x+5=-12/5
- 12 divide by (x+5)=-12 divide by 5
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Similar expressions
- -(3/50)*y=-(12/5)
- 12/(x-5)=-12/5
- (|x|)-(34/5)=-(12/5)
- (((x-1)^2)/5)-((x+4)/6)=((2*(x-1))/3)
- 12/(x+5)=+12/5
12/(x+5)=-12/5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{12}{x + 5} = - \frac{12}{5}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-5\right) 12}{12} = x + 5$$
$$-5 = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 10$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 10$$
Divide both parts of the equation by -1
We get the answer: x = -10
$$\frac{12}{x + 5} = - \frac{12}{5}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 12
b1 = 5 + x
a2 = 1
b2 = -5/12
so we get the equation
$$\frac{\left(-5\right) 12}{12} = x + 5$$
$$-5 = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 10$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 10$$
Divide both parts of the equation by -1
x = 10 / (-1)
We get the answer: x = -10
The graph