Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation sin(x)=0
-
Equation tanx=-sqrt(3)
- Equation a*4a
- Equation 5x-3=3×-11
- Express {x} in terms of y where:
- -7*x+8*y=-14
- -14*x+2*y=8
- -17*x+14*y=-18
- -1*x-15*y=20
- Graphing y =:
- (x-1)2
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Identical expressions
- y-5y+6y=(x- one) two
- y minus 5y plus 6y equally (x minus 1)2
- y minus 5y plus 6y equally (x minus one) two
- y-5y+6y=x-12
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Similar expressions
- y+5y+6y=(x-1)2
- (x^2-4x-12)*√(x^2-16)=0
- 5*x-12=2x+3
- y-5y+6y=(x+1)2
- x^3-3*x^2+3*x-126=0
- y-5y-6y=(x-1)2
- 21*x^2-37*x-120=0
- x^3-x^2+2*x-12=0
y-5y+6y=(x-1)2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
y - 5*y + 6*y = (x - 1)*2
$$6 y + \left(- 5 y + y\right) = 2 \left(x - 1\right)$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the left part:
Move the summands with the unknown x
from the right part to the left part:
$$- 2 x + 2 y = -2$$
Divide both parts of the equation by (-2*x + 2*y)/x
We get the answer: x = 1 + y
y-5*y+6*y = (x-1)*2
Expand brackets in the right part
y-5*y+6*y = x*2-1*2
Looking for similar summands in the left part:
2*y = x*2-1*2
Move the summands with the unknown x
from the right part to the left part:
$$- 2 x + 2 y = -2$$
Divide both parts of the equation by (-2*x + 2*y)/x
x = -2 / ((-2*x + 2*y)/x)
We get the answer: x = 1 + y
The graph
Rapid solution
[src]
x1 = 1 + I*im(y) + re(y)
$$x_{1} = \operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
x1 = re(y) + i*im(y) + 1
Sum and product of roots
[src]
sum
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
=
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
product
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
=
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
1 + i*im(y) + re(y)