Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation x-y=2
-
Equation x^3+2x^2-x-2=0
- Equation (x+20)*(-x+10)=0
-
Equation x^2+8*x+15=0
- Express {x} in terms of y where:
- 15*x+7*y=2
- 12*x-20*y=10
- -17*x-15*y=-17
- 6*x-2*y=20
- Canonical form:
- x^2+2*x+4
- Factor squared:
- x^2+2*x+4
- Derivative of:
-
x^2+2*x+4
-
Identical expressions
- x^ two + two *x+ four = zero
- x squared plus 2 multiply by x plus 4 equally 0
- x to the power of two plus two multiply by x plus four equally zero
- x2+2*x+4=0
- x²+2*x+4=0
- x to the power of 2+2*x+4=0
- x^2+2x+4=0
- x2+2x+4=0
- x^2+2*x+4=O
-
Similar expressions
- x^2+2*x-4=0
- x^2-2*x+4=0
x^2+2*x+4=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 2$$
$$c = 4$$
, then
Because D<0, then the equation
has no real roots,
but complex roots is exists.
or
$$x_{1} = -1 + \sqrt{3} i$$
$$x_{2} = -1 - \sqrt{3} i$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 2$$
$$c = 4$$
, then
D = b^2 - 4 * a * c =
(2)^2 - 4 * (1) * (4) = -12
Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = -1 + \sqrt{3} i$$
$$x_{2} = -1 - \sqrt{3} i$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 2$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -2$$
$$x_{1} x_{2} = 4$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 2$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -2$$
$$x_{1} x_{2} = 4$$
Rapid solution
[src]
___ x1 = -1 - I*\/ 3
$$x_{1} = -1 - \sqrt{3} i$$
___ x2 = -1 + I*\/ 3
$$x_{2} = -1 + \sqrt{3} i$$
x2 = -1 + sqrt(3)*i
Sum and product of roots
[src]
sum
___ ___ -1 - I*\/ 3 + -1 + I*\/ 3
$$\left(-1 - \sqrt{3} i\right) + \left(-1 + \sqrt{3} i\right)$$
=
-2
$$-2$$
product
/ ___\ / ___\ \-1 - I*\/ 3 /*\-1 + I*\/ 3 /
$$\left(-1 - \sqrt{3} i\right) \left(-1 + \sqrt{3} i\right)$$
=
4
$$4$$
4
Numerical answer
[src]
x1 = -1.0 - 1.73205080756888*i
x2 = -1.0 + 1.73205080756888*i
x2 = -1.0 + 1.73205080756888*i
The graph