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x^2+21=10x

x^2+21=10x equation

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Numerical solution:

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The solution

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x  + 21 = 10*x
$$x^{2} + 21 = 10 x$$
Detail solution
Move right part of the equation to
left part with negative sign.

The equation is transformed from
$$x^{2} + 21 = 10 x$$
to
$$- 10 x + \left(x^{2} + 21\right) = 0$$
This equation is of the form
$$a*x^2 + b*x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 1$$
$$b = -10$$
$$c = 21$$
, then
$$D = b^2 - 4 * a * c = $$
$$\left(-1\right) 1 \cdot 4 \cdot 21 + \left(-10\right)^{2} = 16$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = 7$$
Simplify
$$x_{2} = 3$$
Simplify
Vieta's Theorem
it is reduced quadratic equation
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = -10$$
$$q = \frac{c}{a}$$
$$q = 21$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 10$$
$$x_{1} x_{2} = 21$$
The graph
Rapid solution [src]
x_1 = 3
$$x_{1} = 3$$
x_2 = 7
$$x_{2} = 7$$
Sum and product of roots [src]
sum
3 + 7
$$\left(3\right) + \left(7\right)$$
=
10
$$10$$
product
3 * 7
$$\left(3\right) * \left(7\right)$$
=
21
$$21$$
Numerical answer [src]
x1 = 7.0
x2 = 3.0
x2 = 3.0
The graph
x^2+21=10x equation