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x^2+4x+4=0

x^2+4x+4=0 equation

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Numerical solution:

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The solution

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x  + 4*x + 4 = 0
$$\left(x^{2} + 4 x\right) + 4 = 0$$
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 4$$
$$c = 4$$
, then
D = b^2 - 4 * a * c = 

(4)^2 - 4 * (1) * (4) = 0

Because D = 0, then the equation has one root.
x = -b/2a = -4/2/(1)

$$x_{1} = -2$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 4$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -4$$
$$x_{1} x_{2} = 4$$
The graph
Rapid solution [src]
x1 = -2
$$x_{1} = -2$$
x1 = -2
Sum and product of roots [src]
sum
-2
$$-2$$
=
-2
$$-2$$
product
-2
$$-2$$
=
-2
$$-2$$
-2
Numerical answer [src]
x1 = -2.0
x1 = -2.0
The graph
x^2+4x+4=0 equation