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x^2+6*x+19=0 equation

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Numerical solution:

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The solution

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 2               
x  + 6*x + 19 = 0
$$\left(x^{2} + 6 x\right) + 19 = 0$$
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 6$$
$$c = 19$$
, then
D = b^2 - 4 * a * c = 

(6)^2 - 4 * (1) * (19) = -40

Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = -3 + \sqrt{10} i$$
$$x_{2} = -3 - \sqrt{10} i$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 6$$
$$q = \frac{c}{a}$$
$$q = 19$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -6$$
$$x_{1} x_{2} = 19$$
The graph
Sum and product of roots [src]
sum
         ____            ____
-3 - I*\/ 10  + -3 + I*\/ 10 
$$\left(-3 - \sqrt{10} i\right) + \left(-3 + \sqrt{10} i\right)$$
=
-6
$$-6$$
product
/         ____\ /         ____\
\-3 - I*\/ 10 /*\-3 + I*\/ 10 /
$$\left(-3 - \sqrt{10} i\right) \left(-3 + \sqrt{10} i\right)$$
=
19
$$19$$
19
Rapid solution [src]
              ____
x1 = -3 - I*\/ 10 
$$x_{1} = -3 - \sqrt{10} i$$
              ____
x2 = -3 + I*\/ 10 
$$x_{2} = -3 + \sqrt{10} i$$
x2 = -3 + sqrt(10)*i
Numerical answer [src]
x1 = -3.0 + 3.16227766016838*i
x2 = -3.0 - 3.16227766016838*i
x2 = -3.0 - 3.16227766016838*i