Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)-x=0
-
Equation 15-4(7-x)=11
-
Equation x+(8-3x)=12
-
Equation 3*x-4/6=7/8
- Express {x} in terms of y where:
- 2*x+11*y=0
- 14*x-17*y=-4
- 18*x-10*y=-9
- -16*x-14*y=-18
- Derivative of:
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(x^2+1)/(x-1)
- How do you in partial fractions?:
- (x^2+1)/(x-1)
- Graphing y =:
- (x^2+1)/(x-1)
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Identical expressions
- (x^ two + one)/(x- one)= zero
- (x squared plus 1) divide by (x minus 1) equally 0
- (x to the power of two plus one) divide by (x minus one) equally zero
- (x2+1)/(x-1)=0
- x2+1/x-1=0
- (x²+1)/(x-1)=0
- (x to the power of 2+1)/(x-1)=0
- x^2+1/x-1=0
- (x^2+1)/(x-1)=O
- (x^2+1) divide by (x-1)=0
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Similar expressions
- (x^2+1)/(x+1)=0
- (x^2-1)/(x-1)=0
(x^2+1)/(x-1)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} + 1}{x - 1} = 0$$
Multiply the equation sides by the denominators:
-1 + x
we get:
$$\frac{\left(x - 1\right) \left(x^{2} + 1\right)}{x - 1} = 0$$
$$x^{2} + 1 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = 1$$
, then
Because D<0, then the equation
has no real roots,
but complex roots is exists.
or
$$x_{1} = i$$
$$x_{2} = - i$$
$$\frac{x^{2} + 1}{x - 1} = 0$$
Multiply the equation sides by the denominators:
-1 + x
we get:
$$\frac{\left(x - 1\right) \left(x^{2} + 1\right)}{x - 1} = 0$$
$$x^{2} + 1 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = 1$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (1) = -4
Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = i$$
$$x_{2} = - i$$
The graph