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(x^2+5x-3)^2+4(x+6)(x-1)-9=0 equation

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Numerical solution:

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The solution

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\x  + 5*x - 3/  + 4*(x + 6)*(x - 1) - 9 = 0
$$\left(\left(x - 1\right) 4 \left(x + 6\right) + \left(\left(x^{2} + 5 x\right) - 3\right)^{2}\right) - 9 = 0$$
Rapid solution [src]
x1 = -6
$$x_{1} = -6$$
x2 = -4
$$x_{2} = -4$$
x3 = -1
$$x_{3} = -1$$
x4 = 1
$$x_{4} = 1$$
x4 = 1
Sum and product of roots [src]
sum
-6 - 4 - 1 + 1
$$\left(\left(-6 - 4\right) - 1\right) + 1$$
=
-10
$$-10$$
product
-6*(-4)*(-1)
$$\left(-1\right) \left(- -24\right)$$
=
-24
$$-24$$
-24
Numerical answer [src]
x1 = 1.0
x2 = -1.0
x3 = -6.0
x4 = -4.0
x4 = -4.0