Mister Exam
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How to use it?
- Equation:
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Equation x/3/7=9/14
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Equation 2x+9=13-x
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Equation x^2+4x+13=0
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Equation log(3-x)=-1
- Express {x} in terms of y where:
- -17*x-12*y=-4
- 2*x+13*y=-7
- 3*x-9*y=-4
- -4*x-1*y=-6
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Identical expressions
- 2x+ nine = thirteen -x
- 2x plus 9 equally 13 minus x
- 2x plus nine equally thirteen minus x
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Similar expressions
- (x-2)*(x+13)-(x+5)*(x-5)=-23
- (x-1)^3-x^2*(x-3)=8
- 2x-9=13-x
- (x+3)(x+13)-(x-2)(x-3)=6
- cos(pi*(2*x+9)/3)=1/2
- x^9/8+3*x^6/8+3*x^3/8-2*x+9/8=0
- log1(1)(3-x)=log1(1)(4x+13)
- 2x+9=13+x
2x+9=13-x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$2 x = 4 - x$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 4$$
Divide both parts of the equation by 3
We get the answer: x = 4/3
2*x+9 = 13-x
Move free summands (without x)
from left part to right part, we given:
$$2 x = 4 - x$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 4$$
Divide both parts of the equation by 3
x = 4 / (3)
We get the answer: x = 4/3
Sum and product of roots
[src]
sum
4/3
$$\frac{4}{3}$$
=
4/3
$$\frac{4}{3}$$
product
4/3
$$\frac{4}{3}$$
=
4/3
$$\frac{4}{3}$$
4/3
The graph