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x^2+3x-28=0

x^2+3x-28=0 equation

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Numerical solution:

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The solution

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 2               
x  + 3*x - 28 = 0
$$x^{2} + 3 x - 28 = 0$$
Detail solution
This equation is of the form
$$a\ x^2 + b\ x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 1$$
$$b = 3$$
$$c = -28$$
, then
$$D = b^2 - 4\ a\ c = $$
$$3^{2} - 1 \cdot 4 \left(-28\right) = 121$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = 4$$
Simplify
$$x_{2} = -7$$
Simplify
Vieta's Theorem
it is reduced quadratic equation
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 3$$
$$q = \frac{c}{a}$$
$$q = -28$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -3$$
$$x_{1} x_{2} = -28$$
The graph
Rapid solution [src]
x_1 = -7
$$x_{1} = -7$$
x_2 = 4
$$x_{2} = 4$$
Sum and product of roots [src]
sum
-7 + 4
$$\left(-7\right) + \left(4\right)$$
=
-3
$$-3$$
product
-7 * 4
$$\left(-7\right) * \left(4\right)$$
=
-28
$$-28$$
Numerical answer [src]
x1 = 4.0
x2 = -7.0
x2 = -7.0
The graph
x^2+3x-28=0 equation