Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2=12
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Equation 3^x=81
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Equation x^2-8x+12=0
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Equation x^6=-(12-8x)^3
- Express {x} in terms of y where:
- -5*x-6*y=-1
- 1*x+6*y=-6
- -5*x+6*y=-8
- -2*x-9*y=10
- Integral of d{x}:
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(x^2-1)/(x-1)
- Graphing y =:
- (x^2-1)/(x-1)
- How do you in partial fractions?:
- (x^2-1)/(x-1)
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Identical expressions
- (x^ two - one)/(x- one)= zero
- (x squared minus 1) divide by (x minus 1) equally 0
- (x to the power of two minus one) divide by (x minus one) equally zero
- (x2-1)/(x-1)=0
- x2-1/x-1=0
- (x²-1)/(x-1)=0
- (x to the power of 2-1)/(x-1)=0
- x^2-1/x-1=0
- (x^2-1)/(x-1)=O
- (x^2-1) divide by (x-1)=0
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Similar expressions
- (x^2+1)/(x-1)=0
- (x^2-1)/(x+1)=0
(x^2-1)/(x-1)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 1}{x - 1} = 0$$
transform:
$$\frac{\left(x - 1\right) \left(x + 1\right)}{x - 1} = 0$$
$$x + 1 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -1$$
We get the answer: x = -1
$$\frac{x^{2} - 1}{x - 1} = 0$$
transform:
$$\frac{\left(x - 1\right) \left(x + 1\right)}{x - 1} = 0$$
$$x + 1 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -1$$
We get the answer: x = -1
The graph