Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (x+2)^2=(1-x)^2
-
Equation 2*cos(x)+1=0
-
Equation (-5*x-3)*(2*x-1)=0
-
Equation x^2-8x+15=0
- Express {x} in terms of y where:
- 7*x+13*y=-13
- 7*x+19*y=12
- 1*x+20*y=-17
- 14*x-16*y=-3
- Integral of d{x}:
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(x^2-1)/x
- Derivative of:
-
(x^2-1)/x
- Graphing y =:
- (x^2-1)/x
-
Identical expressions
- (x^ two - one)/x= zero
- (x squared minus 1) divide by x equally 0
- (x to the power of two minus one) divide by x equally zero
- (x2-1)/x=0
- x2-1/x=0
- (x²-1)/x=0
- (x to the power of 2-1)/x=0
- x^2-1/x=0
- (x^2-1)/x=O
- (x^2-1) divide by x=0
-
Similar expressions
- (x^2+1)/x=0
(x^2-1)/x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 1}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 1 = 0$$
$$x^{2} - 1 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -1$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 1$$
Simplify
$$x_{2} = -1$$
Simplify
$$\frac{x^{2} - 1}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 1 = 0$$
$$x^{2} - 1 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -1$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-1) = 4
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 1$$
Simplify
$$x_{2} = -1$$
Simplify
Sum and product of roots
[src]
sum
0 - 1 + 1
$$\left(-1 + 0\right) + 1$$
=
0
$$0$$
product
1*-1*1
$$1 \left(-1\right) 1$$
=
-1
$$-1$$
-1
The graph