Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 2x=18-x
-
Equation x^4=(2*x-3)^2
-
Equation 9*x^2=54*x
-
Equation cos(x)+sin(x)=0
- Express {x} in terms of y where:
- -18*x-1*y=-11
- 7*x-2*y=20
- -1*x-20*y=-17
- -2*x-14*y=7
- Factor polynomial:
- 2*x^2-x-1
- Factor squared:
- 2*x^2-x-1
-
Identical expressions
- two *x^ two -x- one =x^ two - five *x-(- one -x^ two)
- 2 multiply by x squared minus x minus 1 equally x squared minus 5 multiply by x minus ( minus 1 minus x squared )
- two multiply by x to the power of two minus x minus one equally x to the power of two minus five multiply by x minus ( minus one minus x to the power of two)
- 2*x2-x-1=x2-5*x-(-1-x2)
- 2*x2-x-1=x2-5*x--1-x2
- 2*x²-x-1=x²-5*x-(-1-x²)
- 2*x to the power of 2-x-1=x to the power of 2-5*x-(-1-x to the power of 2)
- 2x^2-x-1=x^2-5x-(-1-x^2)
- 2x2-x-1=x2-5x-(-1-x2)
- 2x2-x-1=x2-5x--1-x2
- 2x^2-x-1=x^2-5x--1-x^2
-
Similar expressions
- 2*x^2-x-1=x^2-5*x-(1-x^2)
- 2*x^2+x-1=x^2-5*x-(-1-x^2)
- 2*x^2-x-1=x^2-5*x-(-1+x^2)
- 2*x^2-x-1=x^2+5*x-(-1-x^2)
- 2*x^2-x-1=x^2-5*x+(-1-x^2)
- 2*x^2-x+1=x^2-5*x-(-1-x^2)
2*x^2-x-1=x^2-5*x-(-1-x^2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 2 2*x - x - 1 = x - 5*x + 1 + x
$$\left(2 x^{2} - x\right) - 1 = \left(x^{2} + 1\right) + \left(x^{2} - 5 x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$2 x^{2} - x = 2 x^{2} - 5 x + 2$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x^{2} + 4 x = 2 x^{2} + 2$$
Divide both parts of the equation by (2*x^2 + 4*x)/x
We get the answer: x = 1/2
2*x^2-x-1 = x^2-5*x-(-1-x^2)
Expand brackets in the right part
2*x^2-x-1 = x^2-5*x1+x-2
Looking for similar summands in the right part:
-1 - x + 2*x^2 = 1 - 5*x + 2*x^2
Move free summands (without x)
from left part to right part, we given:
$$2 x^{2} - x = 2 x^{2} - 5 x + 2$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x^{2} + 4 x = 2 x^{2} + 2$$
Divide both parts of the equation by (2*x^2 + 4*x)/x
x = 2 + 2*x^2 / ((2*x^2 + 4*x)/x)
We get the answer: x = 1/2
Sum and product of roots
[src]
sum
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
product
1/2
$$\frac{1}{2}$$
=
1/2
$$\frac{1}{2}$$
1/2
The graph