Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (x+2)/9=(x-3)/2
-
Equation 11+2x=55+3x
-
Equation (x-2)^4+3*(x-2)^2-10=0
-
Equation 3*x^2-18=0
- Express {x} in terms of y where:
- 2*x+3*y=14
- 18*x-8*y=-2
- 16*x-7*y=-5
- 10*x-16*y=-6
- Graphing y =:
- (x^2-4)/x
- Derivative of:
-
(x^2-4)/x
- Integral of d{x}:
-
(x^2-4)/x
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Identical expressions
- (x^ two - four)/x= zero
- (x squared minus 4) divide by x equally 0
- (x to the power of two minus four) divide by x equally zero
- (x2-4)/x=0
- x2-4/x=0
- (x²-4)/x=0
- (x to the power of 2-4)/x=0
- x^2-4/x=0
- (x^2-4)/x=O
- (x^2-4) divide by x=0
-
Similar expressions
- (x^2+4)/x=0
(x^2-4)/x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 4}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 4 = 0$$
$$x^{2} - 4 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -4$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 2$$
$$x_{2} = -2$$
$$\frac{x^{2} - 4}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 4 = 0$$
$$x^{2} - 4 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -4$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-4) = 16
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 2$$
$$x_{2} = -2$$
The graph