Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
-
Equation 1/(x-3)^2-3/(x-3)-4=0
-
Equation 2-3(7+2x)=11
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Equation -x-4+5(x+3)=5(-1-x)-2
- Express {x} in terms of y where:
- 17*x-20*y=6
- 5*x-13*y=17
- 6*x+17*y=3
- 1*x+4*y=20
- Graphing y =:
- (x^2-4)/x
- Derivative of:
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(x^2-4)/x
- Integral of d{x}:
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(x^2-4)/x
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Identical expressions
- (x^ two - four)/x= zero
- (x squared minus 4) divide by x equally 0
- (x to the power of two minus four) divide by x equally zero
- (x2-4)/x=0
- x2-4/x=0
- (x²-4)/x=0
- (x to the power of 2-4)/x=0
- x^2-4/x=0
- (x^2-4)/x=O
- (x^2-4) divide by x=0
-
Similar expressions
- (x^2+4)/x=0
(x^2-4)/x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 4}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 4 = 0$$
$$x^{2} - 4 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -4$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 2$$
$$x_{2} = -2$$
$$\frac{x^{2} - 4}{x} = 0$$
Multiply the equation sides by the denominators:
x
we get:
$$x^{2} - 4 = 0$$
$$x^{2} - 4 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -4$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-4) = 16
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 2$$
$$x_{2} = -2$$
The graph