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x^3=4x

x^3=4x equation

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Numerical solution:

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The solution

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 3      
x  = 4*x
$$x^{3} = 4 x$$
Detail solution
Given the equation:
$$x^{3} = 4 x$$
transform
Take common factor x from the equation
we get:
$$x \left(x^{2} - 4\right) = 0$$
then:
$$x_{1} = 0$$
and also
we get the equation
$$x^{2} - 4 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{2} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{3} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = -4$$
, then
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (1) * (-4) = 16

Because D > 0, then the equation has two roots.
x2 = (-b + sqrt(D)) / (2*a)

x3 = (-b - sqrt(D)) / (2*a)

or
$$x_{2} = 2$$
$$x_{3} = -2$$
The final answer for x^3 - 4*x = 0:
$$x_{1} = 0$$
$$x_{2} = 2$$
$$x_{3} = -2$$
Vieta's Theorem
it is reduced cubic equation
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = -4$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = -4$$
$$x_{1} x_{2} x_{3} = 0$$
The graph
Rapid solution [src]
x1 = -2
$$x_{1} = -2$$
x2 = 0
$$x_{2} = 0$$
x3 = 2
$$x_{3} = 2$$
x3 = 2
Sum and product of roots [src]
sum
-2 + 2
$$-2 + 2$$
=
0
$$0$$
product
-2*0*2
$$2 \left(- 0\right)$$
=
0
$$0$$
0
Numerical answer [src]
x1 = 2.0
x2 = 0.0
x3 = -2.0
x3 = -2.0
The graph
x^3=4x equation