Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation -x-2+3*(x-3)=3*(4-x)-3
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Equation x^2=35
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Equation 10*(x-9)=7
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Equation x^2-2x+1=0
- Express {x} in terms of y where:
- -11*x+1*y=12
- 18*x-12*y=-20
- 7*x-2*y=20
- -7*x-7*y=-14
- Integral of d{x}:
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x^2e^2x
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Identical expressions
- x^2e^2x
- x squared e squared x
- x2e2x
- x²e²x
- x to the power of 2e to the power of 2x
x^2e^2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$x e^{2} x^{2} = 0$$
so
$$x = 0$$
We get the answer: x = 0
$$x e^{2} x^{2} = 0$$
so
$$x = 0$$
We get the answer: x = 0
Vieta's Theorem
rewrite the equation
$$x e^{2} x^{2} = 0$$
of
$$a x^{3} + b x^{2} + c x + d = 0$$
as reduced cubic equation
$$x^{3} + \frac{b x^{2}}{a} + \frac{c x}{a} + \frac{d}{a} = 0$$
$$x^{3} = 0$$
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = 0$$
$$x e^{2} x^{2} = 0$$
of
$$a x^{3} + b x^{2} + c x + d = 0$$
as reduced cubic equation
$$x^{3} + \frac{b x^{2}}{a} + \frac{c x}{a} + \frac{d}{a} = 0$$
$$x^{3} = 0$$
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = 0$$