Mister Exam
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How to use it?
- Equation:
- Equation x+y=3
-
Equation x^2-5x+4=0
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Equation 9-4x=3x-40
-
Equation x^2=8
- Express {x} in terms of y where:
- -17*x+18*y=10
- 18*x+12*y=18
- -11*x-3*y=14
- -20*x-13*y=15
-
Identical expressions
- nine -4x=3x- forty
- 9 minus 4x equally 3x minus 40
- nine minus 4x equally 3x minus forty
-
Similar expressions
- 16*x+9-4*x=0
- x^2+3*x-40=0
- 4-3*x=x^2+2*(x^3+3*x-4)^0,5
- 9-4x=3x+40
- 9+4x=3x-40
- (-10*x*x+3*x-40)^2=2*(x*x+1)*(100*x*x-60*x+16)
9-4x=3x-40 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = 3 x - 49$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-7\right) x = -49$$
Divide both parts of the equation by -7
We get the answer: x = 7
9-4*x = 3*x-40
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = 3 x - 49$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-7\right) x = -49$$
Divide both parts of the equation by -7
x = -49 / (-7)
We get the answer: x = 7
The graph