Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation x+y=15
-
Equation (x-4)/x=(2*x+10)/(x+4)
- Equation x^2+p*x+q=0
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Equation 5x-9=3x+1
- Express {x} in terms of y where:
- -13*x+7*y=-17
- -17*x+2*y=3
- 2*x+10*y=-5
- 15*x-18*y=-10
- Canonical form:
- x+y
- x+y
- Limit of the function:
- x+y
- Sum of series:
-
15
- Derivative of:
-
15
- Integral of d{x}:
-
15
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Identical expressions
- x+y= fifteen
- x plus y equally 15
- x plus y equally fifteen
-
Similar expressions
- x-y=15
x+y=15 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$x = 15 - y$$
We get the answer: x = 15 - y
x+y = 15
Looking for similar summands in the left part:
x + y = 15
Move the summands with the other variables
from left part to right part, we given:
$$x = 15 - y$$
We get the answer: x = 15 - y
The graph
Rapid solution
[src]
x1 = 15 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 15$$
x1 = -re(y) - i*im(y) + 15
Sum and product of roots
[src]
sum
15 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 15$$
=
15 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 15$$
product
15 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 15$$
=
15 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 15$$
15 - re(y) - i*im(y)