(x+2)^2=(1-x)^2 equation
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The solution
Detail solution
Given the equation:
(x+2)^2 = (1-x)^2
Expand expressions:
4 + x^2 + 4*x = (1-x)^2
(x+2)^2 = 1 + x^2 - 2*x
Reducing, you get:
3 + 6*x = 0
Move free summands (without x)
from left part to right part, we given:
$$6 x = -3$$
Divide both parts of the equation by 6
x = -3 / (6)
We get the answer: x = -1/2
$$x_{1} = - \frac{1}{2}$$
Sum and product of roots
[src]
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$