Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+2x+1=0
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Equation cos(x)+1=0
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Equation (x+10)2=(5-x)2
- Equation x^2-cos(n*x)*x^2+6*x+9=0
- Express {x} in terms of y where:
- -4*x+4*y=-5
- -11*x+8*y=0
- -2*x-9*y=16
- -12*x-14*y=20
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Identical expressions
- (x+ ten) two =(five -x) two
- (x plus 10)2 equally (5 minus x)2
- (x plus ten) two equally (five minus x) two
- x+102=5-x2
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Similar expressions
- 9*x^4*(25-x^2)=25*(41*x^2-x^4)
- (x+10)2=(5+x)2
- (x-10)2=(5-x)2
- (5-x)^2+(6-x)(6+x)=8x-39
- x^2*(x+102.07)=3.745*10^3
- 2sqrt(x^2+1)+sqrt(x^2+9)=5-x^2
- x^2-20*x+102=0
- 4*(5-x)^(2/3)+(x+5)^(2/3)=5*(25-x^2)^(1/3)
- 3*x^2+18*x+102=0
- (8x+10)(2x^2-4x+10)=0
(x+10)2=(5-x)2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$2 x = - 2 x - 10$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -10$$
Divide both parts of the equation by 4
We get the answer: x = -5/2
(x+10)*2 = (5-x)*2
Expand brackets in the left part
x*2+10*2 = (5-x)*2
Expand brackets in the right part
x*2+10*2 = 5*2-x*2
Move free summands (without x)
from left part to right part, we given:
$$2 x = - 2 x - 10$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -10$$
Divide both parts of the equation by 4
x = -10 / (4)
We get the answer: x = -5/2
Sum and product of roots
[src]
sum
-5/2
$$- \frac{5}{2}$$
=
-5/2
$$- \frac{5}{2}$$
product
-5/2
$$- \frac{5}{2}$$
=
-5/2
$$- \frac{5}{2}$$
-5/2
The graph