Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 5=12-5(4x-1)
-
Equation 10x-20=5x
-
Equation x^2+4*x-32=0
-
Equation 4*(x-6)=x-9
- Express {x} in terms of y where:
- -12*x-2*y=-15
- -4*x+4*y=-9
- -19*x-2*y=-6
- -2*x+2*y=4
-
Identical expressions
- (x+ seven)^ three = nine (x+ seven)
- (x plus 7) cubed equally 9(x plus 7)
- (x plus seven) to the power of three equally nine (x plus seven)
- (x+7)3=9(x+7)
- x+73=9x+7
- (x+7)³=9(x+7)
- (x+7) to the power of 3=9(x+7)
- x+7^3=9x+7
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Similar expressions
- (x+7)^3=9(x-7)
- (x-7)^3=9(x+7)
- absolute(x^2-9x+7)=7
- (x+7)^3=49*(x+7)
(x+7)^3=9(x+7) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\left(x + 7\right)^{3} = 9 \left(x + 7\right)$$
transform:
Take common factor from the equation
$$\left(x + 4\right) \left(x + 7\right) \left(x + 10\right) = 0$$
Because the right side of the equation is zero, then the solution of the equation is exists if at least one of the multipliers in the left side of the equation equal to zero.
We get the equations
$$x + 4 = 0$$
$$x + 7 = 0$$
$$x + 10 = 0$$
solve the resulting equation:
1.
$$x + 4 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -4$$
We get the answer: x1 = -4
2.
$$x + 7 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -7$$
We get the answer: x2 = -7
3.
$$x + 10 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -10$$
We get the answer: x3 = -10
The final answer:
$$x_{1} = -4$$
$$x_{2} = -7$$
$$x_{3} = -10$$
$$\left(x + 7\right)^{3} = 9 \left(x + 7\right)$$
transform:
Take common factor from the equation
$$\left(x + 4\right) \left(x + 7\right) \left(x + 10\right) = 0$$
Because the right side of the equation is zero, then the solution of the equation is exists if at least one of the multipliers in the left side of the equation equal to zero.
We get the equations
$$x + 4 = 0$$
$$x + 7 = 0$$
$$x + 10 = 0$$
solve the resulting equation:
1.
$$x + 4 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -4$$
We get the answer: x1 = -4
2.
$$x + 7 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -7$$
We get the answer: x2 = -7
3.
$$x + 10 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -10$$
We get the answer: x3 = -10
The final answer:
$$x_{1} = -4$$
$$x_{2} = -7$$
$$x_{3} = -10$$
Sum and product of roots
[src]
sum
-10 - 7 - 4
$$\left(-10 - 7\right) - 4$$
=
-21
$$-21$$
product
-10*(-7)*(-4)
$$\left(-4\right) \left(- -70\right)$$
=
-280
$$-280$$
-280
The graph