Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-2x=0
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Equation x^2-3x-10=0
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Equation (x-119)/(x+7)=-5
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Equation x/4+13=x+1
- Express {x} in terms of y where:
- 15*x-5*y=-5
- 18*x+20*y=-2
- 15*x+7*y=2
- 12*x-20*y=10
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Identical expressions
- (x+ one)+(y- one)=(eleven / ten)
- (x plus 1) plus (y minus 1) equally (11 divide by 10)
- (x plus one) plus (y minus one) equally (eleven divide by ten)
- x+1+y-1=11/10
- (x+1)+(y-1)=(11 divide by 10)
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Similar expressions
- x*1(1/10)=11/2
- (x+1)-(y-1)=(11/10)
- 800*x/(11/100)=11/(100*((314/(25*10^7))))
- (x+1)+(y+1)=(11/10)
- 71=(x^2/((0.0036*(57/100+43/((1000*(11/10-x^2/0.0036))))))-1)^2
- (x-1)+(y-1)=(11/10)
(x+1)+(y-1)=(11/10) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
11
x + 1 + y - 1 = --
10
$$\left(x + 1\right) + \left(y - 1\right) = \frac{11}{10}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$x = \frac{11}{10} - y$$
We get the answer: x = 11/10 - y
(x+1)+(y-1) = (11/10)
Expand brackets in the left part
x+1+y-1 = (11/10)
Expand brackets in the right part
x+1+y-1 = 11/10
Looking for similar summands in the left part:
x + y = 11/10
Move the summands with the other variables
from left part to right part, we given:
$$x = \frac{11}{10} - y$$
We get the answer: x = 11/10 - y
The graph
Rapid solution
[src]
11
x1 = -- - re(y) - I*im(y)
10
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + \frac{11}{10}$$
x1 = -re(y) - i*im(y) + 11/10
Sum and product of roots
[src]
sum
11 -- - re(y) - I*im(y) 10
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + \frac{11}{10}$$
=
11 -- - re(y) - I*im(y) 10
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + \frac{11}{10}$$
product
11 -- - re(y) - I*im(y) 10
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + \frac{11}{10}$$
=
11 -- - re(y) - I*im(y) 10
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + \frac{11}{10}$$
11/10 - re(y) - i*im(y)