x+4|x|=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x + 4 x - 3 = 0$$
after simplifying we get
$$5 x - 3 = 0$$
the solution in this interval:
$$x_{1} = \frac{3}{5}$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$4 \left(- x\right) + x - 3 = 0$$
after simplifying we get
$$- 3 x - 3 = 0$$
the solution in this interval:
$$x_{2} = -1$$
The final answer:
$$x_{1} = \frac{3}{5}$$
$$x_{2} = -1$$
$$x_{1} = -1$$
$$x_{2} = \frac{3}{5}$$
Sum and product of roots
[src]
$$-1 + \frac{3}{5}$$
$$- \frac{2}{5}$$
$$- \frac{3}{5}$$
$$- \frac{3}{5}$$