Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation t-4/25=8
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Equation x^2+15=0
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Equation x^2+5*x-14=0
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Equation (x+5)^2=0
- Express {x} in terms of y where:
- 18*x+20*y=-13
- -5*x+15*y=-15
- 5*x+18*y=15
- -1*x-14*y=-8
- Integral of d{x}:
- (x+5)^2
- Graphing y =:
- (x+5)^2
- Inequation:
- (x+5)^2
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Identical expressions
- (x+ five)^ two = zero
- (x plus 5) squared equally 0
- (x plus five) to the power of two equally zero
- (x+5)2=0
- x+52=0
- (x+5)²=0
- (x+5) to the power of 2=0
- x+5^2=0
- (x+5)^2=O
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Similar expressions
- (x-5)^2=0
(x+5)^2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x + 5\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} + 10 x + 25 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 10$$
$$c = 25$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = -5$$
$$\left(x + 5\right)^{2} = 0$$
We get the quadratic equation
$$x^{2} + 10 x + 25 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 10$$
$$c = 25$$
, then
D = b^2 - 4 * a * c =
(10)^2 - 4 * (1) * (25) = 0
Because D = 0, then the equation has one root.
x = -b/2a = -10/2/(1)
$$x_{1} = -5$$
The graph