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(x-3)^2-(x+1)^2=12

(x-3)^2-(x+1)^2=12 equation

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Numerical solution:

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The solution

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       2          2     
(x - 3)  - (x + 1)  = 12
$$\left(x - 3\right)^{2} - \left(x + 1\right)^{2} = 12$$
Detail solution
Given the equation:
(x-3)^2-(x+1)^2 = 12

Expand expressions:
9 + x^2 - 6*x - (x + 1)^2 = 12

9 + x^2 - 6*x - 1 - x^2 - 2*x = 12

Reducing, you get:
-4 - 8*x = 0

Move free summands (without x)
from left part to right part, we given:
$$- 8 x = 4$$
Divide both parts of the equation by -8
x = 4 / (-8)

We get the answer: x = -1/2
The graph
Rapid solution [src]
x1 = -1/2
$$x_{1} = - \frac{1}{2}$$
x1 = -1/2
Sum and product of roots [src]
sum
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
product
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
-1/2
Numerical answer [src]
x1 = -0.5
x1 = -0.5
The graph
(x-3)^2-(x+1)^2=12 equation