(x-3)^2-(x+1)^2=12 equation
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The solution
Detail solution
Given the equation:
(x-3)^2-(x+1)^2 = 12
Expand expressions:
9 + x^2 - 6*x - (x + 1)^2 = 12
9 + x^2 - 6*x - 1 - x^2 - 2*x = 12
Reducing, you get:
-4 - 8*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 8 x = 4$$
Divide both parts of the equation by -8
x = 4 / (-8)
We get the answer: x = -1/2
$$x_{1} = - \frac{1}{2}$$
Sum and product of roots
[src]
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$