Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation -x/12+x=55/12
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Equation 9/(x-2)=9/2
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Equation 2-3*(2*x+2)=5-4*x
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Equation x^4=(4x-21)^2
- Express {x} in terms of y where:
- 4*x+2*y=5
- -10*x-18*y=15
- 2*x-8*y=4
- 7*x-6*y=-10
- Integral of d{x}:
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(x-2)(x+2)
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Identical expressions
- (x- seven)^ two - thirty-three =(x- two)(x+ two)
- (x minus 7) squared minus 33 equally (x minus 2)(x plus 2)
- (x minus seven) to the power of two minus thirty minus three equally (x minus two)(x plus two)
- (x-7)2-33=(x-2)(x+2)
- x-72-33=x-2x+2
- (x-7)²-33=(x-2)(x+2)
- (x-7) to the power of 2-33=(x-2)(x+2)
- x-7^2-33=x-2x+2
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Similar expressions
- (x-4)*(x-6)-(x-2)*(x+2)=-2
- (x-7)^2-33=(x-2)(x-2)
- (x-7)^2-33=(x+2)(x+2)
- (x-7)^2+33=(x-2)(x+2)
- (x+7)^2-33=(x-2)(x+2)
(x-7)^2-33=(x-2)(x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 (x - 7) - 33 = (x - 2)*(x + 2)
$$\left(x - 7\right)^{2} - 33 = \left(x - 2\right) \left(x + 2\right)$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 14 x = -20$$
Divide both parts of the equation by -14
We get the answer: x = 10/7
(x-7)^2-33 = (x-2)*(x+2)
Expand expressions:
49 + x^2 - 14*x - 33 = (x-2)*(x+2)
(x-7)^2-33 = -4 + x^2
Reducing, you get:
20 - 14*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 14 x = -20$$
Divide both parts of the equation by -14
x = -20 / (-14)
We get the answer: x = 10/7
Sum and product of roots
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sum
10/7
$$\frac{10}{7}$$
=
10/7
$$\frac{10}{7}$$
product
10/7
$$\frac{10}{7}$$
=
10/7
$$\frac{10}{7}$$
10/7