Mister Exam
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How to use it?
- Equation:
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Equation sin(x)=√3/2
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Equation sin(x)=-3/2
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Equation (x-1)(x+2)-x(x-3)+5=x+4
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Equation (5-x)^2-x(2,5+x)=0
- Express {x} in terms of y where:
- -4*x-4*y=-19
- -19*x+19*y=20
- 14*x+9*y=-1
- -3*x+20*y=-4
- Derivative of:
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x+4
- Graphing y =:
- x+4
- Integral of d{x}:
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x+4
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Identical expressions
- (x- one)(x+ two)-x(x- three)+ five =x+ four
- (x minus 1)(x plus 2) minus x(x minus 3) plus 5 equally x plus 4
- (x minus one)(x plus two) minus x(x minus three) plus five equally x plus four
- x-1x+2-xx-3+5=x+4
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Similar expressions
- -6=-9(7+x)+4x
- (x-1)(x+2)+x(x-3)+5=x+4
- (x-1)(x-2)-x(x-3)+5=x+4
- (x-1)(x+2)-x(x-3)+5=x-4
- (x+1)(x+2)-x(x-3)+5=x+4
- (x-1)(x+2)-x(x+3)+5=x+4
- (x-1)(x+2)-x(x-3)-5=x+4
(x-1)(x+2)-x(x-3)+5=x+4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
(x - 1)*(x + 2) - x*(x - 3) + 5 = x + 4
$$\left(- x \left(x - 3\right) + \left(x - 1\right) \left(x + 2\right)\right) + 5 = x + 4$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$3 x = 1$$
Divide both parts of the equation by 3
We get the answer: x = 1/3
(x-1)*(x+2)-x*(x-3)+5 = x+4
Expand expressions:
- 2 + 4*x + 5 = x+4
Reducing, you get:
-1 + 3*x = 0
Move free summands (without x)
from left part to right part, we given:
$$3 x = 1$$
Divide both parts of the equation by 3
x = 1 / (3)
We get the answer: x = 1/3
Sum and product of roots
[src]
sum
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
product
1/3
$$\frac{1}{3}$$
=
1/3
$$\frac{1}{3}$$
1/3
The graph