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x-1=1+(1/2)*y equation

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Numerical solution:

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The solution

You have entered [src] 
            y
x - 1 = 1 + -
            2
$$x - 1 = \frac{y}{2} + 1$$
Simplify
Detail solution
Given the linear equation:
x-1 = 1+(1/2)*y

Expand brackets in the right part
x-1 = 1+1/2y

Move free summands (without x)
from left part to right part, we given:
$$x = \frac{y}{2} + 2$$
We get the answer: x = 2 + y/2
The graph
Sum and product of roots [src] 
sum
    re(y)   I*im(y)
2 + ----- + -------
      2        2
$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$ 
=
    re(y)   I*im(y)
2 + ----- + -------
      2        2
$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$ 
product
    re(y)   I*im(y)
2 + ----- + -------
      2        2
$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$ 
=
    re(y)   I*im(y)
2 + ----- + -------
      2        2
$$\frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$ 
2 + re(y)/2 + i*im(y)/2
Rapid solution [src] 
         re(y)   I*im(y)
x1 = 2 + ----- + -------
           2        2
$$x_{1} = \frac{\operatorname{re}{\left(y\right)}}{2} + \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$ 
x1 = re(y)/2 + i*im(y)/2 + 2
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