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Equation
:
Equation x+5=12
Equation -7*x^2+4*x=0
Equation (x+3)(x-2)(x+9)=0
Equation x-log(x^2+1)=0
Express {x} in terms of y where
:
-20*x+12*y=-2
-12*x-1*y=6
-20*x+5*y=3
16*x-18*y=15
Identical expressions
x-log(x^ two + one)= zero
x minus logarithm of (x squared plus 1) equally 0
x minus logarithm of (x to the power of two plus one) equally zero
x-log(x2+1)=0
x-logx2+1=0
x-log(x²+1)=0
x-log(x to the power of 2+1)=0
x-logx^2+1=0
x-log(x^2+1)=O
Similar expressions
x-log(x^2-1)=0
x+log(x^2+1)=0
x-log(x^2+1)=0 equation
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the equation!
The unknown in the equation:
v
Numerical solution:
Do search numerical solution at [
,
]
The solution
You have entered
[src]
/ 2 \ x - log\x + 1/ = 0
$$x - \log{\left(x^{2} + 1 \right)} = 0$$
Simplify
The graph
Plot the graph f1(x)
Plot the graph f2(x)
Numerical answer
[src]
x1 = 0.0
x1 = 0.0
The graph