Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation sin(x)=cos(x)
-
Equation x^3=3
-
Equation cos(x)=(-1/2)
-
Equation sin(x-1)=0
- Express {x} in terms of y where:
- -7*x-20*y=-5
- 5*x-6*y=3
- -20*x+17*y=-16
- -13*x-18*y=1
-
Identical expressions
- x- four /x- six = zero
- x minus 4 divide by x minus 6 equally 0
- x minus four divide by x minus six equally zero
- x-4/x-6=O
- x-4 divide by x-6=0
-
Similar expressions
- 2*(x-4)/(x-6)=0
- x+4/x-6=0
- x-4/x+6=0
x-4/x-6=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\left(x - \frac{4}{x}\right) - 6 = 0$$
Multiply the equation sides by the denominators:
and x
we get:
$$x \left(\left(x - \frac{4}{x}\right) - 6\right) = 0 x$$
$$x^{2} - 6 x - 4 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -6$$
$$c = -4$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 3 + \sqrt{13}$$
$$x_{2} = 3 - \sqrt{13}$$
$$\left(x - \frac{4}{x}\right) - 6 = 0$$
Multiply the equation sides by the denominators:
and x
we get:
$$x \left(\left(x - \frac{4}{x}\right) - 6\right) = 0 x$$
$$x^{2} - 6 x - 4 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -6$$
$$c = -4$$
, then
D = b^2 - 4 * a * c =
(-6)^2 - 4 * (1) * (-4) = 52
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 3 + \sqrt{13}$$
$$x_{2} = 3 - \sqrt{13}$$
Rapid solution
[src]
____ x1 = 3 - \/ 13
$$x_{1} = 3 - \sqrt{13}$$
____ x2 = 3 + \/ 13
$$x_{2} = 3 + \sqrt{13}$$
x2 = 3 + sqrt(13)
Sum and product of roots
[src]
sum
____ ____ 3 - \/ 13 + 3 + \/ 13
$$\left(3 - \sqrt{13}\right) + \left(3 + \sqrt{13}\right)$$
=
6
$$6$$
product
/ ____\ / ____\ \3 - \/ 13 /*\3 + \/ 13 /
$$\left(3 - \sqrt{13}\right) \left(3 + \sqrt{13}\right)$$
=
-4
$$-4$$
-4