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3*80+(n-3)*160 equation

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Numerical solution:

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The solution

You have entered [src]
240 + (n - 3)*160 = 0
$$160 \left(n - 3\right) + 240 = 0$$
Detail solution
Given the linear equation:
3*80+(n-3)*160 = 0

Expand brackets in the left part
3*80+n*160-3*160 = 0

Looking for similar summands in the left part:
-240 + 160*n = 0

Move free summands (without n)
from left part to right part, we given:
$$160 n = 240$$
Divide both parts of the equation by 160
n = 240 / (160)

We get the answer: n = 3/2
Rapid solution [src]
n1 = 3/2
$$n_{1} = \frac{3}{2}$$
n1 = 3/2
Sum and product of roots [src]
sum
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
product
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
3/2
Numerical answer [src]
n1 = 1.5
n1 = 1.5