Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-7*x+10=0
-
Equation 5x^2-8x+3=0
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Equation 3/5*y=29/10-1/5
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Equation -12x+11=-(2-x)
- Express {x} in terms of y where:
- 12*x-20*y=9
- -3*x-10*y=1
- -11*x+16*y=3
- 11*x-6*y=5
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Identical expressions
- x- four (5x+ two)= three (7x- two)
- x minus 4(5x plus 2) equally 3(7x minus 2)
- x minus four (5x plus two) equally three (7x minus two)
- x-45x+2=37x-2
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Similar expressions
- 37x-25x-14=22
- x+4(5x+2)=3(7x-2)
- -2*x^3-4*x^2+37*x-26=0
- x-4(5x+2)=3(7x+2)
- 37x-27x-8x=72
- x-4(5x-2)=3(7x-2)
- 65x^2+637x-2704=0
x-4(5x+2)=3(7x-2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
x - 4*(5*x + 2) = 3*(7*x - 2)
$$x - 4 \left(5 x + 2\right) = 3 \left(7 x - 2\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 19 x = 21 x + 2$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-40\right) x = 2$$
Divide both parts of the equation by -40
We get the answer: x = -1/20
x-4*(5*x+2) = 3*(7*x-2)
Expand brackets in the left part
x-4*5*x-4*2 = 3*(7*x-2)
Expand brackets in the right part
x-4*5*x-4*2 = 3*7*x-3*2
Looking for similar summands in the left part:
-8 - 19*x = 3*7*x-3*2
Move free summands (without x)
from left part to right part, we given:
$$- 19 x = 21 x + 2$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-40\right) x = 2$$
Divide both parts of the equation by -40
x = 2 / (-40)
We get the answer: x = -1/20
Sum and product of roots
[src]
sum
-1/20
$$- \frac{1}{20}$$
=
-1/20
$$- \frac{1}{20}$$
product
-1/20
$$- \frac{1}{20}$$
=
-1/20
$$- \frac{1}{20}$$
-1/20