log(2)(x²-1)=log(2)(2x-1) equation

Move right part of the equation to
left part with negative sign.

The equation is transformed from
$$\left(x^{2} - 1\right) \log{\left(2 \right)} = \left(2 x - 1\right) \log{\left(2 \right)}$$
to
$$- \left(2 x - 1\right) \log{\left(2 \right)} + \left(x^{2} - 1\right) \log{\left(2 \right)} = 0$$
Expand the expression in the equation
$$- \left(2 x - 1\right) \log{\left(2 \right)} + \left(x^{2} - 1\right) \log{\left(2 \right)} = 0$$
We get the quadratic equation
$$x^{2} \log{\left(2 \right)} - 2 x \log{\left(2 \right)} = 0$$
This equation is of the form

a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = \log{\left(2 \right)}$$
$$b = - 2 \log{\left(2 \right)}$$
$$c = 0$$
, then

D = b^2 - 4 * a * c = 

(-2*log(2))^2 - 4 * (log(2)) * (0) = 4*log(2)^2

Because D > 0, then the equation has two roots.

x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 2$$
$$x_{2} = 0$$