Move right part of the equation to left part with negative sign.
The equation is transformed from x2+(x+2)2=102 to (x2+(x+2)2)−102=0 Expand the expression in the equation (x2+(x+2)2)−102=0 We get the quadratic equation 2x2+4x−100+4=0 This equation is of the form ax2+bx+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=2 b=4 c=−96 , then D=b2−4ac= 42−2⋅4(−96)=784 Because D > 0, then the equation has two roots. x1=2a(−b+D) x2=2a(−b−D) or x1=6 Simplify x2=−8 Simplify