Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x=28-x
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Equation (x+3)^2-16=(1-2x)^2
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Equation 0,4(x-3)-1,6=5(0,1x-0,5)
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Equation (x+2)*4+28=(x-2)*2
- Express {x} in terms of y where:
- 17*x-7*y=15
- -18*x+16*y=4
- -11*x-6*y=1
- -13*x-5*y=6
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Identical expressions
- two x two -2x- twelve =(x+2)2
- 2x2 minus 2x minus 12 equally (x plus 2)2
- two x two minus 2x minus twelve equally (x plus 2)2
- 2x2-2x-12=x+22
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Similar expressions
- (x^2-2*x)^2-2*(x-1)^2-1=0
- (x*2-x-6)sqrt(x-1)=2x*2-2x-12
- 2*x^2-2*x-12=x^2-4
- 3x+2*(2x-3)=8-7*(x-2)
- 2x2-2x-12=(x-2)2
- 2x2+2x-12=(x+2)2
- (x^2+2x)-(x+2)(2x^2-x)=6(2x-1)^2
- 2x2-2x+12=(x+2)2
- -(x+2)^2+4=0
- (x+2)^2=(x-4)^2
- (1/2)(x^2-2(x-1)^2)=1-(1/4)
2x2-2x-12=(x+2)2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2*x2 - 2*x - 12 = (x + 2)*2
$$\left(- 2 x + 2 x_{2}\right) - 12 = 2 \left(x + 2\right)$$
The graph
Rapid solution
[src]
re(x2) I*im(x2)
x1 = -4 + ------ + --------
2 2
$$x_{1} = \frac{\operatorname{re}{\left(x_{2}\right)}}{2} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{2} - 4$$
x1 = re(x2)/2 + i*im(x2)/2 - 4
Sum and product of roots
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sum
re(x2) I*im(x2)
-4 + ------ + --------
2 2
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{2} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{2} - 4$$
=
re(x2) I*im(x2)
-4 + ------ + --------
2 2
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{2} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{2} - 4$$
product
re(x2) I*im(x2)
-4 + ------ + --------
2 2
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{2} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{2} - 4$$
=
re(x2) I*im(x2)
-4 + ------ + --------
2 2
$$\frac{\operatorname{re}{\left(x_{2}\right)}}{2} + \frac{i \operatorname{im}{\left(x_{2}\right)}}{2} - 4$$
-4 + re(x2)/2 + i*im(x2)/2