Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (25+x)-10=40
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Equation x^3+5*x^2-4*x-20=0
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Equation x^2+4*x=21
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Equation x^3+x-1=0
- Express {x} in terms of y where:
- 13*x+3*y=6
- -9*x+1*y=20
- 7*x-18*y=-4
- 5*x-13*y=-1
- Graphing y =:
- -(x+2)^2+4
-
Identical expressions
- -(x+ two)^ two + four = zero
- minus (x plus 2) squared plus 4 equally 0
- minus (x plus two) to the power of two plus four equally zero
- -(x+2)2+4=0
- -x+22+4=0
- -(x+2)²+4=0
- -(x+2) to the power of 2+4=0
- -x+2^2+4=0
- -(x+2)^2+4=O
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Similar expressions
- -(x-2)^2+4=0
- (x+2)^2+4=0
- -(x+2)^2-4=0
-(x+2)^2+4=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$4 - \left(x + 2\right)^{2} = 0$$
We get the quadratic equation
$$- x^{2} - 4 x = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -1$$
$$b = -4$$
$$c = 0$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = -4$$
$$x_{2} = 0$$
$$4 - \left(x + 2\right)^{2} = 0$$
We get the quadratic equation
$$- x^{2} - 4 x = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -1$$
$$b = -4$$
$$c = 0$$
, then
D = b^2 - 4 * a * c =
(-4)^2 - 4 * (-1) * (0) = 16
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = -4$$
$$x_{2} = 0$$