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2x^2-18=2

2x^2-18=2 equation

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Numerical solution:

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The solution

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   2         
2*x  - 18 = 2
$$2 x^{2} - 18 = 2$$
Detail solution
Move right part of the equation to
left part with negative sign.

The equation is transformed from
$$2 x^{2} - 18 = 2$$
to
$$\left(2 x^{2} - 18\right) - 2 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 0$$
$$c = -20$$
, then
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (2) * (-20) = 160

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = \sqrt{10}$$
Simplify
$$x_{2} = - \sqrt{10}$$
Simplify
Vieta's Theorem
rewrite the equation
$$2 x^{2} - 18 = 2$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} - 10 = 0$$
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = -10$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 0$$
$$x_{1} x_{2} = -10$$
The graph
Rapid solution [src]
        ____
x1 = -\/ 10 
$$x_{1} = - \sqrt{10}$$
       ____
x2 = \/ 10 
$$x_{2} = \sqrt{10}$$
Sum and product of roots [src]
sum
      ____     ____
0 - \/ 10  + \/ 10 
$$\left(- \sqrt{10} + 0\right) + \sqrt{10}$$
=
0
$$0$$
product
     ____   ____
1*-\/ 10 *\/ 10 
$$\sqrt{10} \cdot 1 \left(- \sqrt{10}\right)$$
=
-10
$$-10$$
-10
Numerical answer [src]
x1 = 3.16227766016838
x2 = -3.16227766016838
x2 = -3.16227766016838
The graph
2x^2-18=2 equation