Mister Exam
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How to use it?
- Equation:
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Equation (x+6)^2=(15-x)^2
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Equation 9^x+2*3^x-3=0
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Equation 2*x=1
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Equation -3+x/5=x+2/3
- Express {x} in terms of y where:
- -11*x-14*y=6
- 18*x+20*y=-3
- 3*x+2*y=-4
- -8*x+16*y=11
- Graphing y =:
- x+2/3
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Identical expressions
- - three +x/ five =x+ two / three
- minus 3 plus x divide by 5 equally x plus 2 divide by 3
- minus three plus x divide by five equally x plus two divide by three
- -3+x divide by 5=x+2 divide by 3
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Similar expressions
- -3+x/5=x-2/3
- -3-x/5=x+2/3
- 3+x/5=x+2/3
- tan((17/10)*x)+(2/3*x)=0
- 2*x/(x+2)-(x-1)/(x-3)=10*(x+2)/(3-x)
- 3^((x+2)/(3x−4))−7=2⋅3^((5x−10)/(3x−4))
-3+x/5=x+2/3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = x + \frac{11}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{5} = \frac{11}{3}$$
Divide both parts of the equation by -4/5
We get the answer: x = -55/12
-3+x/5 = x+2/3
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = x + \frac{11}{3}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{5} = \frac{11}{3}$$
Divide both parts of the equation by -4/5
x = 11/3 / (-4/5)
We get the answer: x = -55/12
Sum and product of roots
[src]
sum
-55 ---- 12
$$- \frac{55}{12}$$
=
-55 ---- 12
$$- \frac{55}{12}$$
product
-55 ---- 12
$$- \frac{55}{12}$$
=
-55 ---- 12
$$- \frac{55}{12}$$
-55/12
The graph