Move right part of the equation to left part with negative sign.
The equation is transformed from (2x2−14x)+10=8 to ((2x2−14x)+10)−8=0 This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D = b^2 - 4*a*c - it is the discriminant. Because a=2 b=−14 c=2 , then
D = b^2 - 4 * a * c =
(-14)^2 - 4 * (2) * (2) = 180
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or x1=235+27 x2=27−235
Vieta's Theorem
rewrite the equation (2x2−14x)+10=8 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2−7x+1=0 px+q+x2=0 where p=ab p=−7 q=ac q=1 Vieta Formulas x1+x2=−p x1x2=q x1+x2=7 x1x2=1