Mister Exam
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How to use it?
- Equation:
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Equation 49*x^3+14*x^2+x=0
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Equation 4^x=8
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Equation x^2-x=12
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Equation x-5(x+3)=5
- Express {x} in terms of y where:
- -7*x-13*y=-12
- -3*x+19*y=16
- -4*x+4*y=-9
- -19*x-2*y=-6
- Integral of d{x}:
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4x+12
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Identical expressions
- 4x+ twelve =3x+ eight
- 4x plus 12 equally 3x plus 8
- 4x plus twelve equally 3x plus eight
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Similar expressions
- (x+1)^4-4(x+1)^2-21=0
- 2(x+3)(x+8)-2x(x+8)=(x+3)(x+8)
- 2*(4*(x+1)^2/(x^2+2*x-3)-1)/(x^2+2*x-3)^2=0
- 60-2,2*(3x-2)=4(x+12)
- 4*x+12=3*x+8
- 4x-12=3x+8
- 4x+12=3x-8
4x+12=3x+8 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$4 x = 3 x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$x = -4$$
We get the answer: x = -4
4*x+12 = 3*x+8
Move free summands (without x)
from left part to right part, we given:
$$4 x = 3 x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$x = -4$$
We get the answer: x = -4
The graph