Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 49*x^3+14*x^2+x=0
-
Equation 4^x=8
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Equation x^2-x=12
-
Equation x-5(x+3)=5
- Express {x} in terms of y where:
- -7*x-13*y=-12
- -3*x+19*y=16
- -4*x+4*y=-9
- -19*x-2*y=-6
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Identical expressions
- two x- two (x+ seven)= three (2-x)
- 2x minus 2(x plus 7) equally 3(2 minus x)
- two x minus two (x plus seven) equally three (2 minus x)
- 2x-2x+7=32-x
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Similar expressions
- (x-3)^2-(x+1)^2=12
- sqrt^32-x=-5
- 2x+2(x+7)=3(2-x)
- (x-3)^2-x(x+2,7)=9
- (x+3)^2-(x-3)^2=4*x^2-16
- 2x-2(x-7)=3(2-x)
- 2x-2(x+7)=3(2+x)
2x-2(x+7)=3(2-x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2*x - 2*(x + 7) = 3*(2 - x)
$$2 x - 2 \left(x + 7\right) = 3 \left(2 - x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$0 = 20 - 3 x$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 20$$
Divide both parts of the equation by 3
We get the answer: x = 20/3
2*x-2*(x+7) = 3*(2-x)
Expand brackets in the left part
2*x-2*x-2*7 = 3*(2-x)
Expand brackets in the right part
2*x-2*x-2*7 = 3*2-3*x
Looking for similar summands in the left part:
-14 = 3*2-3*x
Move free summands (without x)
from left part to right part, we given:
$$0 = 20 - 3 x$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 20$$
Divide both parts of the equation by 3
x = 20 / (3)
We get the answer: x = 20/3
Sum and product of roots
[src]
sum
20/3
$$\frac{20}{3}$$
=
20/3
$$\frac{20}{3}$$
product
20/3
$$\frac{20}{3}$$
=
20/3
$$\frac{20}{3}$$
20/3