Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x^2-12*x+12=0
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Equation 5(x-2,2)=7x
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Equation -2x=4
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Equation 10/(6-x)=4/(x+2)
- Express {x} in terms of y where:
- 4*x+5*y=7
- 4*x-2*y=4
- -19*x+10*y=11
- 16*x-9*y=-17
- Derivative of:
- 2(x-1)
- Integral of d{x}:
- 2(x-1)
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Identical expressions
- two (x- one)= three (x+ one)
- 2(x minus 1) equally 3(x plus 1)
- two (x minus one) equally three (x plus one)
- 2x-1=3x+1
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Similar expressions
- x^3+3x^2+3x+1=0
- x-5/4=7-2x-11/3
- (x-7)^2=10x^2-(3x-1)(3x+1)
- 2(x-1)=3(x-1)
- x^3-2x^2+12x-18=0
- -7x+4=2x-14
- 2(x+1)=3(x+1)
- 2*3^(x+1)-3^x=15
- (1/2)x-1=0,25
- 2*sin(3x)+1=0
- cot(3*x)+1=0
- 2-(2x-15)=-5(3+2x)
2(x-1)=3(x+1) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$2 x = 3 x + 5$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 5$$
Divide both parts of the equation by -1
We get the answer: x = -5
2*(x-1) = 3*(x+1)
Expand brackets in the left part
2*x-2*1 = 3*(x+1)
Expand brackets in the right part
2*x-2*1 = 3*x+3*1
Move free summands (without x)
from left part to right part, we given:
$$2 x = 3 x + 5$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 5$$
Divide both parts of the equation by -1
x = 5 / (-1)
We get the answer: x = -5