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- Equation:
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Equation 3*x^2-12*x+12=0
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Equation 5(x-2,2)=7x
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Equation -2x=4
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Equation 10/(6-x)=4/(x+2)
- Express {x} in terms of y where:
- 4*x+5*y=7
- 4*x-2*y=4
- -19*x+10*y=11
- 16*x-9*y=-17
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Identical expressions
- two -(2x- fifteen)=- five (three +2x)
- 2 minus (2x minus 15) equally minus 5(3 plus 2x)
- two minus (2x minus fifteen) equally minus five (three plus 2x)
- 2-2x-15=-53+2x
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Similar expressions
- 2-(2x+15)=-5(3+2x)
- 2-(2x-15)=+5(3+2x)
- 2-(2x-15)=-5(3-2x)
- -5*(3+2*x*y)+8-2*x=0
- (X^2+2x-8)^(x^2-2x-15)=1
- x^2-2x-15=(x+3)*(x-5)=0
- (x^2-2*x-24)*(x^2-2*x-15)=0
- 2+(2x-15)=-5(3+2x)
- (2x+3)/(x^2-2x-15)=0
2-(2x-15)=-5(3+2x) equation
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The solution
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2 + -2*x + 15 = -5*(3 + 2*x)
$$\left(15 - 2 x\right) + 2 = - 5 \left(2 x + 3\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 10 x - 32$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = -32$$
Divide both parts of the equation by 8
We get the answer: x = -4
2-(2*x-15) = -5*(3+2*x)
Expand brackets in the left part
2-2*x+15 = -5*(3+2*x)
Expand brackets in the right part
2-2*x+15 = -5*3-5*2*x
Looking for similar summands in the left part:
17 - 2*x = -5*3-5*2*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 10 x - 32$$
Move the summands with the unknown x
from the right part to the left part:
$$8 x = -32$$
Divide both parts of the equation by 8
x = -32 / (8)
We get the answer: x = -4
The graph