Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x+7*4=40
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Equation 2x^2-x=0
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Equation -x=3,5
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Equation x-log(x^2+1)=0
- Express {x} in terms of y where:
- 2*x-9*y=-10
- 13*x-12*y=0
- 20*x+2*y=-1
- 11*x+19*y=-4
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Identical expressions
- two (two +y)= nineteen +3y
- 2(2 plus y) equally 19 plus 3y
- two (two plus y) equally nineteen plus 3y
- 22+y=19+3y
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Similar expressions
- -21-17*y=219+3*y
- (3+4y)(y−1)−(3y−2)(2+y)=10−5y
- (x-2)^2+y^2=4
- (3+4y)(y-1)-(3y-2)(2+y)=10-5y
- 2(2+y)=19-3y
- 2*(2+y)=19-3*y
- 2(2-y)=19+3y
2(2+y)=19+3y equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without y)
from left part to right part, we given:
$$2 y = 3 y + 15$$
Move the summands with the unknown y
from the right part to the left part:
$$- y = 15$$
Divide both parts of the equation by -1
We get the answer: y = -15
2*(2+y) = 19+3*y
Expand brackets in the left part
2*2+2*y = 19+3*y
Move free summands (without y)
from left part to right part, we given:
$$2 y = 3 y + 15$$
Move the summands with the unknown y
from the right part to the left part:
$$- y = 15$$
Divide both parts of the equation by -1
y = 15 / (-1)
We get the answer: y = -15