Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation -5+9x=10x+4
-
Equation 25*x^3-10*x^2+x=0
-
Equation -x=5
-
Equation x/3+x/12=15/4
- Express {x} in terms of y where:
- 15*x+12*y=-19
- -19*x-20*y=-4
- -18*x+12*y=-8
- -14*x+4*y=-16
- Derivative of:
-
2*x^2+3*x
- Graphing y =:
- 2*x^2+3*x
- Limit of the function:
-
2*x^2+3*x
-
Identical expressions
- two *x^ two + three *x= zero
- 2 multiply by x squared plus 3 multiply by x equally 0
- two multiply by x to the power of two plus three multiply by x equally zero
- 2*x2+3*x=0
- 2*x²+3*x=0
- 2*x to the power of 2+3*x=0
- 2x^2+3x=0
- 2x2+3x=0
- 2*x^2+3*x=O
-
Similar expressions
- 2*x^2-3*x=0
2*x^2+3*x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 3$$
$$c = 0$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 0$$
$$x_{2} = - \frac{3}{2}$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 3$$
$$c = 0$$
, then
D = b^2 - 4 * a * c =
(3)^2 - 4 * (2) * (0) = 9
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 0$$
$$x_{2} = - \frac{3}{2}$$
Vieta's Theorem
rewrite the equation
$$2 x^{2} + 3 x = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + \frac{3 x}{2} = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = \frac{3}{2}$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = - \frac{3}{2}$$
$$x_{1} x_{2} = 0$$
$$2 x^{2} + 3 x = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + \frac{3 x}{2} = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = \frac{3}{2}$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = - \frac{3}{2}$$
$$x_{1} x_{2} = 0$$
Sum and product of roots
[src]
sum
-3/2
$$- \frac{3}{2}$$
=
-3/2
$$- \frac{3}{2}$$
product
0*(-3) ------ 2
$$\frac{\left(-3\right) 0}{2}$$
=
0
$$0$$
0
The graph